RE: arbitrary sorting (Part IV)

> I want to sort my elements (<element 
> month="Jul">...</element>) in the 
> same order as in <monthtab>. Note: there's no explizit number given in
> monthtab. Any ideas how to solve that? 
> (perhaps by using position() somehow ...)

Tricky, because there's no XPath facility to determine the position of a
node relative to its siblings: you can only do this using <xsl:number/>, and
you can't invoke XSLT-level operations while computing a sort key. Not until
the next Saxon release, anyway, which will allow you to implement external
XPath functions in XSLT. But if you you're prepared to go outside the
standard, the whole problem becomes very easy!

Mike Kay


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