Hello, I have the following XML hierarchy: <bucket> <object id="first" x="35" y="10" /> <object id="second" x="15" y="58" /> <subbucket> <object> <id>third</id> <x>28</x> <y>145</y> </object> </subbucket> <object id="fourth" x="65" y="27" /> </bucket> Ok, enough with the funny looks. I know that the use of id, x, and y should be consistent as either children or an attribute. ; ). But, this is what I'm dealing with now, until I can get it changed. I'd like to be able to sort all four objects based on the value of their "y"s, regardless of whether they are a child or an attribute. Is that possible? Doing two sorts, with one being the major and the other the minor will not work. I think it has to be in one xsl:sort. Any help is greatly appreciated. Thanks, Brian Young XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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