Off-topic: XML and DTD

This is off-topic, but...

what you need is a DOCTYPE declaration in your XML document pointing to the
DTD, like this:

<!DOCTYPE foo SYSTEM "http://www.foo.com/foo.dtd">

where foo is the name of your root element and the string in quotes is a
relative or absolute URI pointing to the DTD that is associated with the
document. Typically, this appears just after the <?xml...?> declaration.
When a validating parser reads this document, it will load the specified DTD
and validate the document against it.

HTH...

- Kevin

Kevin Williams
XML Architect
Ultraprise Corporation

> -----Original Message-----
> From: Mar Fior [mailto:pupipai@xxxxxxxxxxx]
> Sent: Thursday, June 01, 2000 10:07 AM
> To: xsl-list@xxxxxxxxxxxxxxxx
> Subject: XML and DTD
> 
> 
> 
> Hi,
> I don't know xml very well and my question is stupid!!!
> I have created an file xml and another file dtd for that
> xml.
> When I call my xml file from my browser (IE)
> I can see it well formatted. But I don't know how I must do
> to see if it is "VALID".
> I have inserted into my xml file this row:
> 
> <?xml version="1.0" standalone="no"?>
> 
> Because if I have understood well
> "stanalone" identify with "yes" if I want that the check
> is only "well fomatted" and with "no" if the check
> is "valid document".
> 
> But the result is equal. And If I add some error into
> my xml file I haven't any segnalation!
> 
> How I can do to know if my xml file have the rule of
> his dtd????
> 
> 
> Please, help me!
> Thanks in advance and sorry for my little english!
> 
> Marcella
> 
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