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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: passing a parameter to select attribute of <xsl:sort>
Ryan and Nick,
Well, you could try the old hack:
<xsl:apply-templates select="./listItem">
<xsl:sort order="{$order}" select="*[local-name()=$orderingElement]"/>
</xsl:apply-templates>
Nick's explanation is essentially correct (except the select attribute
doesn't take a pattern, it takes a string evaluated as an expression, not
quite the same thing). This solution (warning:untested) would get around it
by constructing such an expression that tests element names, as strings,
against the variable (rather than assuming the variable can be used to
select a node set relative to the context node, which it can't).
Hope this helps,
Wendell
At 10:06 PM 6/21/00 +0100, you wrote:
>Ryan, as I understand from the XSLT spec and Mike Kays book (p 119) you
cannot do all
>that you want to in one go. The select attribute cannot use an attribute
value template
>though the order attribute can. The reason being that select requires an
XPath pattern.
>I guess the way round this is with a choose/when/when/.../otherwise
construct with each
>of the possible sort conditions explicitly stated.
>
>Or is there another way ?
>
>Regards
>
>Nick Browne
>Slipstone Ltd
>
>
>Ryan Daigle wrote:
>
>> I am trying to pass a parameter into a sort element through another
>> template as follows:
>> ...
>> <xsl:apply-templates select="./listItem">
>> <xsl:sort order="{$order}" select="$orderingElement"/>
>> </xsl:apply-templates>
>> </xsl:template>
======================================================================
Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
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