RE: variable and match

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Subject: RE: variable and match
From: Ross Cormier <merex@xxxxxxxx>
Date: Fri, 12 May 2000 07:34:34 -0500

OK, then how can I dynamically create a template in XSLT?

See the following for an example of what I am trying to do.

Thanks,
Ross

Original XML: <ROWSET> <REPLACE EL="FOO"/> <--I want to use this element to tell the xsl what to replace--> <FOO> <DATA1>data1</DATA1> <DATA1>data1</DATA1> </FOO> </ROWSET>

After Transform:
<ROWSET>
  <NEWELEMENT>
    <DATA1>data1</DATA1>
    <DATA1>data1</DATA1>
  </NEWELEMENT>
</ROWSET>

Another example:
<ROWSET>
  <REPLACE EL="BAZ"/>
  <BAZ>
    <DATA1>data1</DATA1>
    <DATA1>data1</DATA1>
  </BAZ>
</ROWSET>

After Transform:
<ROWSET>
  <NEWELEMENT>
    <DATA1>data1</DATA1>
    <DATA1>data1</DATA1>
  </NEWELEMENT>
</ROWSET>

The FOO|BAZ element could be one of 30 different elements and new ones are added all of the time, so I dont want to do something like this: <xsl:template match="/ROWSET/FOO|FOOBAR|BAZ"> <NEWELEMENT><xsl:apply-templates/></NEWELEMENT> </xsl:template>

At 09:51 AM 5/12/00 +0100, you wrote:

> Can I use a variable in the match part of xsl:template?
>
>
> <xsl:variable name="x" select="/ROWSET/REPLACE/@EL"/>
> <xsl:template match="/ROWSET/{$x}">

No, you can't, neither can you use curly braces. In any case, you've got the
wrong model of what variables are: you can't use them to do textual
substitution of one bit of XPath syntax into another bit of XPath syntax.

Mike Kay

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

Current Thread
RE: variable and match Kay Michael - Fri, 12 May 2000 09:51:48 +0100 Ross Cormier - Fri, 12 May 2000 07:34:34 -0500 <= Eric van der Vlist - Fri, 12 May 2000 16:01:41 +0200 <Possible follow-ups> Kay Michael - Fri, 12 May 2000 15:22:26 +0100 Kevin Williams - Fri, 12 May 2000 11:20:45 -0400

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