Re: ### Outputting the "full path". Is this possible ?? ###
Is there a way to get the same effect but via a template? Otherwise for each element from the source document to the destination document I have to repeat the code. I would have had that if there were an XSLT standard function, like xsl:path-of. Khalid ----- Original Message ----- From: "David Carlisle" <davidc@xxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxx> Sent: Friday, May 26, 2000 10:16 AM Subject: Re: ### Outputting the "full path". Is this possible ?? ### > but what if an element contains a sequence of elements, such as > > <departments> > <employees> > <name>Joe Shmo</name> > <name>Bob Shmo</name> > </employees> > </departments> > > > <xsl:for-each select="(ancestor-or-self::*)" > >/*[<xsl:value-of select="1+count(preceding-sibling::*)"/>]</xsl:for-each> > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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