RE: Why don't this work?

nodeName() is not a node selector, and cannot be used outside a filter [].
In XSLT, the equivalent function name() can be used in certain places like
value-of select="" but still not in apply-templates or match.  A node's name
is a property of the node, not a node itself.

- Jonathan Marsh
  Microsoft

> -----Original Message-----
> From: Westerlund, Malin [mailto:malin.westerlund@xxxxxxxxxx]
> Sent: Thursday, April 06, 2000 4:33 AM
> To: 'xsl-list@xxxxxxxxxxxxxxxx'
> Subject: Why don't this work?
> 
> 
> I'm trying to get the tagname, but it doesn't seem to work.  
> I'm not so good
> at this so I might have done something  very wrong. The 
> node() works but not
> the nodeName().
> 
> 
> <?xml version="1.0"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl"
> 	xmlns="http://www.w3.org/TR/REC-html40">
> 
> <xsl:template match="/">
> 	<TABLE>
> 	<TR>
> 		<xsl:for-each select="*/element()">
> 		<TD>
> 		<xsl:apply-templates select="./nodeName()"/>
> 		</TD>
> 		</xsl:for-each>
> 	</TR>
> 		<xsl:for-each select="*/element()">	
> 		<TR>
> 			<TD>
> 				<xsl:apply-templates select="./node()"/>
> 			</TD>
> 		</TR>
> 		</xsl:for-each> 
> 	</TABLE>
> </xsl:template>	
> 
> <xsl:template match="./nodeName()">
> 	<xsl:value-of /><td/>
> </xsl:template>
> 	
> <xsl:template match="./node()">
> 	<xsl:value-of /><td/>
> </xsl:template>
> 
> </xsl:stylesheet>
> 
> I'm using msxml3
> 
> regards
> 
> Malin
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


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