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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Dereferencing an XPath variable
I know that the subject is meaningless ;-)
Is it possible to write an XSLT template that, matching the following
source node
<my:A>
<my:apply-templates select="<<xpath>>"/>
<my:B/>
</my:A>
calls <xsl:apply-templates select="<<xpath>>"/>?
After reading XPath spec carefully I really believe that it is NOT possible.
Am I right? Any proposal?
Follows a wrong solution (only to explain what I need):
<xsl:template match="my:A">
<xsl:variable name="select" select="@select"/>
<xsl:apply-templates select="$select"/>
</xsl:template>
Thanks in advance,
C.S.C.
--
-----------------------------------------
Real Name: Claudio Sacerdoti Coen
Undergraduate Student at cs.unibo.it
Address: via del Colle n.6
S. Lazzaro di Savena (BO)
Italy
e-mail: sacerdot@xxxxxxxxxxx
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XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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