RE: parameter setting

Use concat function should solve this problem

<xsl:value-of select="concat($param1, '')"/> 

- Prasad

> -----Original Message-----
> From:	vanaja  gogineni [SMTP:vanaja_g@xxxxxxxxxxx]
> Sent:	Wednesday, April 19, 2000 3:04 PM
> To:	xsl-list@xxxxxxxxxxxxxxxx
> Subject:	RE: parameter setting
> 
> Thanku
> 
> I tried like that but still
> 
> I am unable to get it, I removed
> 
> select also it is not working .
> 
> is there any other way pl suggest me.
> 
> Thanks &regards
> 
> vanaja
> --
> 
> On Wed, 19 Apr 2000 09:10:22   Selva, Francis wrote:
> >Well I guess the reason is you have the string 'output' as ur default
> value
> >which overwrites your actual parameter.If you remove the select
> attribute,it
> >will work.
> >
> >Francis
> >
> > 
> >> my xsl looks like this
> >> ----------------------------------------------
> >> it is a top level parameter
> >> 
> >> <xsl:param name="param1" select="'output'"/>
> >> 
> >> and I am using this variable in-between
> >> like this
> >> 
> >> <xsl:value-of select="$param1"/>
> >> 
> >> 
> >> result is
> >> 
> >> "output"
> >> 
> >> but I want "vanaja" to be displayed
> >> 
> >> what is the wrong with this
> >> 
> >> 
> >> Thanks & regards
> >> 
> >> Vanaja
> >> 
> > 
> >
> >
> > XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> >
> 
> 
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