Re: Displaying every 2 element values in 1 row

ok, this works all fine and dandy for that example, but with a more complicated
example this gets wacked.

XML(imagine there is data in there ;]):
<company>
  <department>
   <name></name>
   <person>
     <name></name>
   </person>
   <person>
     <name></name>
   </person>
  </department>
  <department>
   <name></name>
   <person>
     <name></name>
   </person>
   <person>
     <name></name>
   </person>
  </department>
  <department>
   <name></name>
   <person>
     <name></name>
   </person>
   <person>
     <name></name>
   </person>
  </department>
  <department>
   <name></name>
   <person>
     <name></name>
   </person>
   <person>
     <name></name>
   </person>
 </department>
</company>

so I basicly want this output:
<tr><td>DEPARTMENT 1</td>DEPARTMENT 2</td></tr>
<tr><td>DEPARTMENT 3</td>DEPARTMENT 4</td></tr>

so this would be the <td> part:
<xsl:template match="department">
    <td>
        <xsl:value-of select="name" /><br />
        <ul>
            <xsl:apply-templates select="person" />
        </ul>
    </td>
</xsl:template>

<xsl:template match="person">
    <li><xsl:value-of select="name" /></li>
</xsl:template>

this is slightly over-slimplified, but it shows the problem I am having of that I
am not trying to call a <xsl:value-of> as the contents of the tiling, but calling
an <xsl:apply-templates>. the "following-sibling" returns a node-set that
consists of "all nodes that start after the end of the current node and have the
same parent as the current node"("XML Bible" Table 14-2). The problem is that the
first time you call the "following-sibling" it returns the following <person> and
all other <person> elements in the <department> element. This is fine if there
are only 2 <person> elements in a <department>. If there are 3 or more, it causes
some nasty recursion that I have yet to figure out how to avoid.

Thanks for any help in advance,

Noah Nordrum
p.s. This time I will also check the list archives, since it appears I'm not
getting 100% of the messages from the list :)

Mike Brown wrote:

> > How can I display every two element node values in one row by checking the
> > position?
> >
> > If I have an xml like:
> >
> > <eno>A21</eno>
> > <eno>A22</eno>
> > <eno>A23</eno>
> > <eno>A24</eno>
> > <eno>A25</eno>
> > <eno>A26</eno>
>
> <!-- look at every 1st, 3rd, 5th, etc 'eno' element child of current node -->
> <xsl:for-each select="eno[position() mod 2 = 1]">
>   <!-- start a new table row -->
>   <tr>
>     <!-- cell 1: value of current 'eno' -->
>     <td>
>       <xsl:value-of select="."/>
>     </td>
>     <!-- cell 2: value of next 'eno' or a non-breaking space if none -->
>     <td>
>       <xsl:choose>
>         <xsl:when test="following-sibling::eno">
>           <xsl:value-of select="following-sibling::eno"/>
>         </xsl:when>
>         <xsl:otherwise>&#160;</xsl:otherwise>
>     </td>
>   </tr>
> </xsl:for-each>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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