Accessing 2 xml files from one xsl

I solved the problem by doing this.Im getting the right output.But I want to
know whether this is the right way or there is a easy way to do what I need.

<xsl:template match="/">
<xsl:apply-templates select="document('bw.xml')"/>
</xsl:template>

<xsl:template match="/"> 
 all my layout stts
</xsl:template>

Which one is better?.To create one template match and then giving all the
node names in the condition while getting the values or having different
templates match for each category? 

Thanx
Francis


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