How to give an URL file path

How do I specify a url file path instead of a full path like
"c:\programs\apache group\apache" when I try to read a xml file as
XSLTInputSource.  Currently, I hardcoded the following:

XSLTInputSource xslSource = new XSLTInputSource ("e://Programs/Apache_JServ
1.1/servlets/foo.xsl");

I have the following system configuration:

Http Server: Apache 1.3.12 for WinNT4.0
Servlet Engine: Apache JServ1.1 for WinNT4.0

Any help would be appreciated.  Thanks.

Micheal
huan_loh@xxxxxxx 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list