Re: using default params?

> David,
> very nice explanation of xsl:copy-of

hmm but it obviously didn't have the intended effect of explaining
the code:-)

> But could you explain further how the code you present would set a default
> value for the attribute?
> 
> > 
> > <table border="1001" >
> >   <xsl:copy-of select="@border"/>

(I corrected a typo in my original: it had ! instead of ", which 
is easily done if typing on a UK keyboard with your eyes closed,
and a duplicated word border which was added by a cosmic ray after I
posted the message)


<table border="1001" >

makes a n element node with name table
and one attribute node with name border

<xsl:copy-of select="@border"/>

either does nothing, in which case you get what you have above
or it generates an attribute node with name border.
XSLT specifies that if you add two attribute nodes of the same name to
an element the first one is discarded. So in this case  the original
attribute node with value 1001 is replaced by the border attribute
copy-of'ed from the source tree.

So effectively you get a copy of the original except that you get a
default value of 1001 in the case when there was no border attribute
originally.

David


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