sort,count,number,group solved

    Over a week later, and I have solved the puzzle I posed here
earlier.  Thanks to everyone who replied.  Hope this is useful to
someone.

Here is my original posting, solution follows.

" After perusing the FAQ I can sort, count, number, and group.
    But I cannot do them all at once.  Please help.

    Example:

xml:

<root>
    <foo>
          <bar>bard</bar>
          <bar>bark</bar>
    </foo>
    <foo>
          <bar>bark</bar>
          <bar>barb</bar>
     </foo>
</root>

Sample xsl that selects distinct <bar>

<xsl:template match="//bar[not(. = following::bar)]">
     <xsl:value-of select="."/>
</xsl:template>

produces:

bard bark barb

what I want is to number these, sort them, and count the number of times

they appear in the xml source

Desired output:

1.  barb  -1
2.  bard  -1
3.  bark  -2

I can't seem to get there from here.  Do I need to use for-each?

Thanks,
            -Quagly"


My solution:

 <xsl:template match="/">
 <DL>
 <xsl:apply-templates select="//bar[not(. = preceding::bar)]">
 <xsl:sort select="bar"/>
 </xsl:apply-templates>
 </DL>
</xsl:template>


<xsl:template match="bar">
 <DT>
 <xsl:number value="position()" format="1."/>
 <xsl:value-of select="."/>-
 <xsl:value-of select="count(//bar[.=current()])"/>
 </DT>
</xsl:template>
</xsl:stylesheet>


It is amazing to me how easy this is now that I see it.  I got very
caught up in for-eaches and variable assignments.
Please critique this for me.  Can it be improved?  Is there some
ingenious principle I have tapped into that can be articulated?
Or let me know if this is helpful to you.





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