RE: Node with maximum attribute value

Maybe I didn't explain all of the problem so well.

I want to use the variable in an XPath outside of the xsl:for-each, ie in
another scope.

The following code works, but it could hardly be called elegant.


<!-- Iterate over a descending node-set -->
<xsl:for-each select="closing-price">
<xsl:sort data-type="number" select="@mid" order="descending"/>

<!-- Choose only the first node (ie largest) -->
<xsl:if test="position()=1">
<xsl:variable name="MaxValue" select="@mid" />

<!-- Now iterate over the list again in original sort order -->
<xsl:for-each select="closing-price">

<!-- Do Something with $MaxValue -->

</xsl:for-each>


</xsl:if>
</xsl:for-each>





Richard
ps Sorry about the encoding

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxx]On Behalf Of David Carlisle
> Sent: 21 February 2000 18:05
> To: xsl-list@xxxxxxxxxxxxxxxx
> Subject: Re: Node with maximum attribute value
>
>
>
> why did you mime encode that?
>
> however...
>
> > My first idea was to use a sorted for-each, and assign a variable to
> > the maximum value, however variables cannot be reassigned. Is there
> > another way?
>
> use your first idea then use
>
> <xsl:if test="position()=last()">maximum = <xsl:value-of
> select="@mid"/></xsl:if>
>
> as the template body of the for-each.
>
> David
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list