Re: Where can I find the XSLT DTD?

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Subject: Re: Where can I find the XSLT DTD?
From: "John E. Simpson" <simpson@xxxxxxxxxxx>
Date: Thu, 03 Feb 2000 11:57:46 -0500

At 05:00 PM 2/3/2000 +0100, Yann Desnoues wrote:

Linda van den Brink wrote:

> There's an appendix to the XSLT spec "DTD Fragment for XSLT Stylesheets
> (Non-Normative)" at http://www.w3.org/TR/xslt#dtd
>
> I hope it's any help to you...

Thank you but it doesn't help as it is not a complete DTD.
The entity result-elements is not defined.
Hence the DTD is not valid.

Of course result-elements is not defined. It *can't* be.

If you're transforming to HTML, then there's one "valid XSLT DTD" with one definition of result-elements. If you're transforming to MathML, there's a completely different result-elements. In fact, there are as many definitions of result-elements as there are possible XML vocabularies in the universe. Hence there can *be* no result-elements, and that's why the appendix to the XSLT Rec is both a fragment and non-normative.

=============================================================
John E. Simpson
simpson@xxxxxxxxxxx
-------------------------------------------------------------
I put contact lenses in my dog's eyes. They had little
pictures of cats on them. Then I took one out and he ran
around in circles.  (Stephen Wright)

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

Current Thread

Where can I find the XSLT DTD?
- Yann Desnoues - Thu, 03 Feb 2000 13:42:05 +0100
  - <Possible follow-ups>
  - Linda van den Brink - Thu, 3 Feb 2000 14:44:24 +0100
    - Yann Desnoues - Thu, 03 Feb 2000 17:00:32 +0100
      - David Carlisle - Thu, 3 Feb 2000 16:19:38 GMT
      - John E. Simpson - Thu, 03 Feb 2000 11:57:46 -0500 <=
      - Yann Desnoues - Thu, 03 Feb 2000 19:16:27 +0100
      - John E. Simpson - Thu, 03 Feb 2000 14:16:11 -0500
      - Lars Marius Garshol - 03 Feb 2000 22:16:12 +0100
      - Rick Geimer - Thu, 03 Feb 2000 14:55:59 -0800

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