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RE: document() revisited

Subject: RE: document() revisited
From: Linda van den Brink <lvdbrink@xxxxxxx>
Date: Wed, 16 Feb 2000 13:15:25 +0100
linda beckers
To enter each listed file, do something like

<xsl:for-each select="file">
	<xsl:param name="current_file_root" select="."/>
		<xsl:for-each select="document($current_file_root)">
		<!-- do your stuff here -->

I don't know what you mean by copying the result onto itself. Do you want
the result to be available for further processing? Then you need to store it
in a variable as a result tree fragment using copy-of and access the
variable with an extension function such as XT and Saxon have. It's not
possible in standard XSLT. 


> -----Original Message-----
> From: Beckers, Marc [mailto:Marc.Beckers@xxxxxxxxxxxxxx]
> Sent: Wednesday, February 16, 2000 11:49 AM
> To: 'xsl-list@xxxxxxxxxxxxxxxx'
> Subject: document() revisited
> I've asked this before and got no replies,
> so I'll ask again and try and put the question more simply:
> I have an xml document containing a list of xhtml files, e.g.:
> <mother>
>   <file>files\overview.html</file>
>   <file>files\book1\page1.html</file>
>   <file>files\book1\chap1\page2.html</file>
>   <file>files\book2\page1.html</file>
>   <file>files\book2\chap1\page2.html</file>
> </mother>
> How can I use XSL to enter each listed file,
> manipulate it and copy the result onto itself,
> thus retaining the file names and directory structure?
> Grateful for any tips or hints
> Dr. Marc Beckers
> Documentation Consultant
> Software AG
> Uhlandstraße 12
> D-64297 Darmstadt
> Phone +49-6151-92-1322
> Fax              -1612
> mailto:Marc.Beckers@xxxxxxxxxxxxxx
> http://www.softwareag.com
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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