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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Getting a longest node
Esteemed XSLers:
Does anyone know a way I could define a variable that would contain the
number of characters in the longest node in a node-set? Let the node set in
question be //DIV[@type='Chapter']: if I have three, with string lengths
88888, 99999, and 111110, I want my variable to be 111110.
I tried iterating over the node set and resetting a variable if it passes
the greater-than test --
<xsl:template name="getlongest">
<xsl:param name="nodeset"/>
<xsl:param name="longest" select="0">
<xsl:for-each select="$nodeset">
<xsl:if test="string-length(.) > $longest">
<xsl:variable name="longest" select="string-length(.)">
</xsl:if>
</xsl:for-each>
<xsl:value-of select="$longest"/>
</xsl:template>
But of course since the reset variable is only scoped within the
xsl:for-each, all I get back is zero. :->
I think I know I have to do this with some kind of recursion, but I can't
get my head around how. Can anyone with a fresh mind think of the solution?
A good way to warm up on a Monday? I'll give you credit in my stylesheet....
TIA!
Wendell Piez
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Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
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Mulberry Technologies: A Consultancy Specializing in SGML and XML
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XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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