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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Copying unparsed entity using XSL
I have a xml document like this: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE Job SYSTEM "doc.dtd" [ <!ENTITY pcl0001 SYSTEM "pcl0001.pcl" NDATA BINARY> ]> <Job> <Print/> </Job> I would like to obtain the identity trasformation using something like: <xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template> but I want that the Entity: <!ENTITY pcl0001 SYSTEM "pcl0001.pcl" NDATA BINARY> is in the output file. Is this possible using XSLT (and XT or LotusXSL or ..) ? Thanks in advance. Bye. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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