RE: Accessing the XML declaration, the namespace-uri() funct

>Date: Thu, 4 Nov 1999 17:48:58 -0700 
>From: Mike Brown <mbrown@xxxxxxxxxxxxx>
>Subject: RE: Accessing the XML declaration, the namespace-uri()
function
>
>Dylan Walsh wrote:
>> Is it possible to somehow access the attributes of the <?xml
>> version="1.0"?> tag?
>
>No. An XML parser looks at the XML declaration so that it can know how
to go
>about interpreting the character data that comprises the rest of the
>document. The declaration is not fed by the XML parser into your XSL
>processor.

It seems you can with IE5. The default XML viewer stylesheet uses
<xsl:template match="pi('xml')>
as I've mentioned in another post. Alas this isn't possible with up to
date XSL.

>> I'm trying to create a stylesheet that will generate a
>> HTML view of any XML code
>
>A stylesheet that generates an HTML view of XML *code* is one thing. A
>stylesheet that generates an HTML view of the *node tree* that XML code
>*represents* is something altogether different.

What I have created is a stylesheet which gives you a view of your XML
file in your web browser via standard HTML.
The code is indented and highlighted i.e. the output when viewed in a
brower looks like your XML code, only indented & color coded.
Mine does everything except show the <?XML?> declaration and the
namespaces.

>> Would it be safe to assume that the declaration is always
>> <?xml version="1.0"?> and hard code it, i.e.:
>> &lt;?xml version="1.0"?&gt; ?
>
>No, it's not safe to assume. If you are trying to HTMLize the code (of
which
>the XML declaration and entity references are a part) and not the node
tree,
>then you need to avoid feeding the XML source document to your XSL
processor
>in a manner that causes the document to be split up into the tree of
nodes
>that the document represents. (i.e., good luck.) I suspect that you are
>actually trying to HTMLize the node tree, which doesn't contain the XML
>declaration or the DTD (yet), so you need to not be worrying about it.

Perhaps I've explained my goal more clearly above ("What I have created
is...").
What I am proposing here is a cheat, which assumes we'll be using <?xml
version="1.0"?> for a while to come.

>> Also, does the namespace-uri() function work in XT? [...]
>> I can't get it to produce anything (using <xsl:value-of
>> select="namespace-uri()> ).

><xsl:value-of select="namespace-uri(foo)"/> will create in the result
tree a
>text node containing the namespace URI of the first node in the
node-set
>identified by the XPath location path 'foo'.
>http://www.w3.org/TR/xpath#section-Node-Set-Functions explains several
>situations which will cause this function to return an empty string.
And if
>you omit the argument, then the context node will be used. Are you sure
your
>context node has a namespace?
>
>- -Mike

I'd like elements which declare names spaces to have xmlns:foo="uri" in
my output, as they do in the source. I've made some progress with
namespace-uri(), but I don't think I'll be able to do what I want to
until XT supports the namespace axis (which will allow me to show the
name of the namespace).


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list