[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

Re: Remove duplicates from a list

Subject: Re: Remove duplicates from a list
From: Tim Taylor <ttaylor@xxxxxxxxxx>
Date: Fri, 29 Oct 1999 17:20:48 -0400
java list remove duplicates
I have a similar, but more complicated problem.  Given the following XML
snippet:

    <skill title="java"/>
    <skill title="perl"/>
    <skill title="java"/>

I would like to transform to:

    java
    perl

Actually, there's a bit more to this.  The source XML is more like:

    <employee id="ttaylor">
        <skill title="java"/>
    </employee>

    <employee id="jdoe">
        <skill title="perl"/>
        <skill title="java"/>
    </employee>

And the desired tranformation (order unimportant):

    <h2>java</h2>
    <ol>
        <li>ttaylor</li>
        <li>jdoe</li>
    </ol>

    <h2>perl</h2>
    <ol>
        <li>jdoe</li>
    </ol>

However, I already figured out the XSL for generating the list of
employees with a skill, given a list of skill nodes.  I'm in search of
the XSL for the simpler problem stated above, i.e. listing the first
occurance of an element for each title attribute.  Starting with Clark
Evans' example, I have tried variations on the following idea with no
success:

    <xsl:variable name="unique-list"
        select="//employee/skill[ 
            not (. = following::skill[@title = current()/@title]) ]"/>

I'm sure I mustn't be grokking something.  I succesfully used a similar
approach to generate the list of employees.  The following will
transform to the desired output, sans removal of skill following the
first occurance:

    <xsl:for-each select="//employee/skill">
        <h2><xsl:value-of select="@title"/></h2>
        <ol>
            <xsl:for-each
select=".|following::skill[@title=current()/@title]
                <li><xsl:value-of select="parent::employee/@id"/></li>
            </xsl:for-each>
        </ol>
    </xsl:for-each>

Also, since this is really a learning excercise of my own creation, I'm
really after comprehension more than the solution.  Please explain the
solution, or provide pointers to information explaining it.  Feel free
to only address the simpler problem above.  I provided the more
complicated examples mostly as background info.

Much thanks,
Tim


"Clark C. Evans" wrote:
> 
>   <xsl:variable name="unique-list"
>     select="//state[not(.=following::state)]" />
> 
>   <xsl:for-each select="$unique-list">
>         <xsl:value-of select="." />
>   </xsl:for-each>
> 
> On Wed, 27 Oct 1999, Minita Jha wrote:
> >  <location>
> >    <state>xxxx</state>
> >  </location>
> >
> >  <location>
> >     <state>yyyy</state>
> >  </location>
> >
> >   <location>
> >     <state>xxxx</state>
> >  </location>
> >
> >  The desired output is:
> >
> >    xxxx
> >    yyyy
> >
> >  That is, duplicate values of state should not be printed.
> >  Can this be done?
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

-- 
Tim Taylor


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread

PURCHASE STYLUS STUDIO ONLINE TODAY!

Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!

Buy Stylus Studio Now

Download The World's Best XML IDE!

Accelerate XML development with our award-winning XML IDE - Download a free trial today!

Don't miss another message! Subscribe to this list today.
Email
First Name
Last Name
Company
Subscribe in XML format
RSS 2.0
Atom 0.3
Site Map | Privacy Policy | Terms of Use | Trademarks
Free Stylus Studio XML Training:
W3C Member
Stylus Studio® and DataDirect XQuery ™are products from DataDirect Technologies, is a registered trademark of Progress Software Corporation, in the U.S. and other countries. © 2004-2013 All Rights Reserved.