Re: Accessing the element stack generically

These should be exactly the elements on the
ancestor-or-self axis so a select="ancesor-or-self::*"
should return the node list of elements
including yourself in the "stack" (in reverse document order)


________________________________________________________
Steve Muench, BC4J Development Team & XML Evangelist
http://technet.oracle.com/tech/java
http://technet.oracle.com/tech/xml
----- Original Message ----- 
From: Clark C. Evans <clark.evans@xxxxxxxxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxx>
Sent: Friday, October 15, 1999 9:30 AM
Subject: Accessing the element stack generically


| 
| Hello.  I have an xml document:
| 
| <a><b><c/></b><c/></a>
| 
| I'd like to, when match="c" is invoked, print
| the current element stack.  Any generic way to do this?
| 
|  /a/b/c and /a/c are what I'm after...
| 
| Harder version:
| 
|  <a><b x="y"><c/></b><b x="z"><c/></b></a>
| 
| Print the element stack including parameters to get:
| 
|  /a/b[@x='y']/c  and /a/b[@x='z']/c
| 
| Thanks for any suggestions.
| 
| clark
| 
| 
|  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
| 


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