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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] choose on element content.
given
<INDI ID='I001'>
<NAME>John Derek <S>Montalt (Moult)</S></NAME>
<SEX>M</SEX>
I need conditional processing, dependent on the sex of
the NAMEd person.
I'm getting a syntax error with
<xsl:template match="INDI">
<xsl:choose>
<xsl:when test="[string(SEX)='M']">
^^^^^^^^^^^^^^^^^^ syntax error.^^^^^^^^^^^^^
<xsl:element name="a">
<xsl:attribute name="href">#<xsl:value-of
select="id(FAMS/@REF)/WIFE/@REF"/>
</xsl:attribute>Spouse:
<xsl:value-of select="id(id(FAMS/@REF)/WIFE/@REF)/NAME"/>
</xsl:element>
</xsl:when>
<xsl:otherwise>
<xsl:element name="a">
<xsl:attribute name="href">#<xsl:value-of
select="id(FAMS/@REF)/HUSB/@REF"/>
</xsl:attribute>Spouse:
<xsl:value-of select="id(id(FAMS/@REF)/HUSB/@REF)/NAME"/>
</xsl:element>
</xsl:otherwise>
</xsl:choose>
I need to check if the content of an element is M or F.
I tried
<xsl:when test="SEX/text()='M'">
which also gave the syntax error.
any suggestions please?
DaveP
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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