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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Query on xsl:if
 I'm trying to create a stylesheet to output on IE5. I'm having problem using the xsl:if tag. The following are the files. XML File: <?xml version="1.0"?> <!DOCTYPE PERSON SYSTEM "PERSON.DTD"[ ]> <?xml-stylesheet type="text/xsl" href="person1.xsl" ?> <PERSON> <NAME NAME_VALUE="Chicago"/> <ADDRESS><![CDATA[Hello & World]]></ADDRESS> <CITY/> <USER_TYPE USER_TYPE_VALUE="Hello"/> </PERSON> XSL File: <?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl">
<xsl:template match="/">
<HTML>
<STYLE>
TD {font-size:9pt}
</STYLE>
<BODY STYLE="font:9pt Verdana">
<TABLE>
<TR>
<TD colspan="10" align="LEFT">
DATE
</TD>
<TD colspan="15">
TIME
</TD>
<TD colspan="100" ALIGN="RIGHT">
CLAIM
</TD>
</TR>
</TABLE>
<p align="center"><xsl:value-ofselect="PERSON/NAME/@NAME_VALUE"/></p>
<xsl:if match="PERSON/NAME[@NAME_VALUE= 'Chicago']">
Hello World
</xsl:if>
</BODY>
</HTML>
</xsl:template>
</xsl:stylesheet>What could be wrong with the xsl:if tag which does not produce the output in IE5 while <xsl:value-of select> would output the correct value? TIA. CU, Malliks ______________________________________________________ Get Your Private, Free Email at http://www.hotmail.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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