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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: getting xsl to produce ill-formed xml?
 I got several suggestions for this problem:
1. (John Simpson) Generate a CDATA block.
I don't see how this can be done (Oren seems to confirm this
in his <Opinion> element).
2. (Duane Nickul) Post-process with perl.
But that is what I was already doing.
It is the principle of the thing. If I was going to be using
perl, this little exercise would have been done long ago.
I wanted an excuse to play with xsl.
3. (Oren Ben-Kiki) Use <SCRIPT>.
This works, but now I don't get the exact output I wanted --
I've got this "# <SCRIPT>" in the perl program itself.
It is like letting xsl win; not acceptable :).
(Again, I've already got a working system... a reasonable
definition of a hacker is someone who takes a working
system and "improves" it....)
4. (Duane Nickul) Use an entity.
This almost works. If I put this in my style sheet:
<!DOCTYPE xsl:stylesheet SYSTEM "xsl.dtd" [
<!ENTITY plarrow "=>">
]>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl">
...
<xsl:text>
<
&plarrow;
</xsl:text>
Then I get this in the output:
<
=>
I might note that this also holds if I use this stylesheet
declaration:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl"
xmlns:html="http://www.w3.org/TR/REC-html40"
result-ns="html">
In other words, I can't seem to get xt to expand all entities
I insert (like "<"), and worse yet, it seems to want to
convert any ">" in sight to a ">".
I don't know if this is an xsl thing or an xt thing.
(In general, I've yet to find that xt does much different
based on the stylesheet declaration except maybe put a line like
this across the top of the output:
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
.)
-mda
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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