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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] How can I get real path ?
Imagine I have the following XML instance :
<?xml version="1.0"?>
<description>
<document>
<name>a name</name>
<status>a status</status>
<name>a name</name>
</document>
</description>
I want to get something like :
1 description
1.1 document
1.1.1 name
1.1.2 status
1.1.3 name
'path(this)' can't give me what I want.
path gives me :
1 description
1.1 document
1.1.1 name
1.1.1 status // <= that's not what I want
I can't figure out how to do that. Is there any other solution ?
Note : I use MSXSL.Exe.
benoit.barre@xxxxxxxxxx
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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