Literal NaNDavid Carlisle davidc at nag.co.uk
Mon Feb 28 16:36:57 PST 2011
On 25/02/2011 15:29, David Lee wrote: > Or have to use conversion to string , or maybe something equally obtuse > > You can test if $x is a NaN using the predicate $x = $x which is false for NaN and true for other numeric values. David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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