XQuery count()

[Ricardo Queirós]

Thanks to all.
Both Wolfgang approaches work well.

Regards!

2009/11/9 G. Ken Holman <http://x-query.com/mailman/listinfo/talk>

> At 2009-11-09 18:55 +0000, Ricardo Queirós wrote:
>
>> I need to count the total number of distinct collections in my db (eXist
>> XML Database).
>>
>
> How are you defining "distinct" in your situation?  There are many possible
> ways:  string value, tree structure, tree structure of string values, etc.
>
>
>  How can i do this in a compact way using XQuery?
>>
>
> Consider using deep-equal() ... if you have two root nodes, say in $a and
> $b, you can get true/false with deep-equal( $a, $b ) and it will check the
> tree structure and the node values in the tree structure and things like
> attributes will be checked regardless of their order (because attributes in
> XML documents are unordered).
>
> But be aware this is an "expensive" function, and could take up a lot of
> processing resources to accomplish the comparison.
>
> I hope this helps.
>
> . . . . . . . . . . . Ken
>
>
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-- 
Ricardo Queirós
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