XQuery - RegEx Pattern Matcher

[Michael Kay]

The XPath regular expression language does not recognize \G and it does not
recognize non-capturing groups. 

As far as matches() is concerned, there is no distinction between capturing
and non-capturing groups, so replace "(?:" by "(".

I suspect you wanted your regex to contain "\G". In Java you need to escape
this as "\\G"; in XPath/XQuery, backslash is not a special character and
does not need to be escaped. However, there's no "\G" in XPath regular
expressions anyway. In Java it means "the end of the previous match"; but
XQuery is a functional language, so "previous" is meaningless. At this stage
I give up because I'm not sure what you are trying to do: you haven't
supplied enough of your code.

Regards,

Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay  

> -----Original Message-----
> From: http://x-query.com/mailman/listinfo/talk 
> [mailto:http://x-query.com/mailman/listinfo/talk] On Behalf Of http://x-query.com/mailman/listinfo/talk
> Sent: 19 June 2009 09:33
> To: http://x-query.com/mailman/listinfo/talk
> Subject:  XQuery - RegEx Pattern Matcher
> 
> Hi,
> I am trying to use a RegEx within XQuery. In general that works fine.
> Now I have a more complex RegEx to work with CSV-files(these 
> CSV have ";" as separator).
> I use can the following without problems in Java :
> 
> Pattern Regex = Pattern.compile(
> "\\G(?:^|;)(?:\"((?:[^\"]|\"\")*)\"|([^\";]*))");
> ...
> 
> But in XQuery
> let $regularExpr :='\\G(?:^|;)(?:\"((?:[^\"]|\"\")*)\"|([^\";]*))'
> ...
> if (matches($row,$regularExpr) ) then ( ...
> 
> just gives the error :
> 
> Error at character 4 in regular expression 
> "\\G(?:^|;)(?:\"((?:[^\"]|\"\")...": expected ())
> 
> 
> I tried the optional flags (i, x, ...) but always with the 
> same result...
> What is wrong with this RegEx ?
> 
> P.S. :I run the XQuery from Java with Saxon.
> 
> 
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