returning elements without duplicates, based on an XML schema and using an attribute as context node

[Philip Cantin]

Hello All,

I am new to this mailing list, as well as fairly new to XQuery and XPath
(having learned it for a month or two). For the most part, I haven't had too
much trouble editing an old XQuery document, until now.

I am trying to access the 'maxOccurs' attribute within the for-loop, where
$ref is the 'ref' attribute, and return distinct <xf:bind> elements with no
duplicate elements. However, I can't seem to set the $max variable properly
using XPath functions, without getting an error. I imagine it must have
something to do with setting/finding/using the current context.


The XQuery code looks like this:


if (exists($schema//xs:element[exists(@maxOccurs) and @maxOccurs != '1']))
then (
   for $ref in distinct-values($schema//xs:element[exists(@maxOccurs) and
@maxOccurs != '1' and @maxOccurs ne 'unbounded']/@ref)
      let $name := string($ref)
      let $max := string($ref//following-sibling::maxOccurs)
      let $index_max := ($max cast as xs:integer)
      return
         <xf:bind
            id="{concat($name, '-add-trigger')}"
            nodeset="instance('views')/{$name}-add-trigger"
            relevant="instance('save-data')//{$name}[{$index_min}]" />

)
else ()
};


and the XML schema code looks (very) roughly like this - and the only
purpose of showing this is to help illustrate what I'd like to do:

<xs:schema>

   <xs:element name="a">
      <xs:complexType>
         <xs:sequence>
            <xs:element ref="e" maxOccurs="2" />
            <xs:element ref="g" maxOccurs="3" />
         </xs:sequence>
      </xs:complexType>
   </xs:element>

   <xs:element name="b">
      <xs:complexType>
         <xs:sequence>
            <xs:element ref="j" maxOccurs="2" />
            <xs:element ref="g" maxOccurs="3" />
         </xs:sequence>
      </xs:complexType>
   </xs:element>

</xs:schema>


Can someone show me the proper way to access the maxOccurs attribute from
the ref attribute, and/or provide me with a link that can help me understand
this situation a little more?

Thanks much in advance!


~PJC
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