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[XQuery Talk Mailing List Archive Home] [By Date] [By Thread] [By Subject] [By Author] [Recent Entries] [Reply To This Message] xpath/xquery to eleminate certain nodesChristian Schlaefcke cschlaefcke at wms-network.deTue Aug 26 17:12:38 PDT 2008
Thank you John! looks promising! But after I tried to adapt it to my application I have some trouble with XmlBeans and Saxon that I use to run my queries. After I found out that xquery uptate was not available with the XmlBeans/Saxon versions I used (2.3.0/8.7) I upgraded to versions (2.4.0/9.1.0.1) and now I get this error: Error on line 3 column 9 XPST0003: XQuery syntax error in #...$this external; copy $#: Unexpected token "copy" in path expression My query looks like this: declare namespace mns='http://www.mynamespace.com'; copy $a := / modify delete node $a/mns:sites/mns:site//mns:categories/mns:category[@id = "888"] return $a Did someone encounter this problem before? Thanks & Regards, Christian > Hi Christian, > > XQuery Update can be used to solve your problem fairly easily - > something like this should do the trick: > > copy $a := / > modify delete nodes $a/site/sites//categories/category[@name = 'hidden'] > return $a > > John > > Christian Schlaefcke wrote: >> Hi, >> >> I am fighting with a xpath/xquery expression to select the whole xml >> document except of certain nodes that I want to remove. The general >> structure of the document should be preserved. >> >> With my approaches I either select too much or too less and my research >> @ >> google & co. did not bring me any further :-( >> >> The document structure is a bit tricky (arbitrarily nested categories) - >> imagine the following document: >> <sites> >> <site> >> <categories> >> <category name="root"> >> <categories> >> <category name="category_1"> >> <some> >> <further> >> <nested> >> <info info_id="1">Important Information</info> >> </nested> >> </further> >> </some> >> </category> >> <category name="category_2"> >> <some> >> <further> >> <nested> >> <info info_id="2">Less Important Information</info> >> </nested> >> </further> >> </some> >> </category> >> </categories> >> </category> >> <category name="hidden"> >> <categories> >> <category name="dont_need_it"> >> <some> >> <further> >> <nested> >> <info info_id="3">Unimportant Information</info> >> </nested> >> </further> >> </some> >> </category> >> <category name="dont_need_it_too"> >> <some> >> <further> >> <nested> >> <info info_id="4">Even More Unimportant >> Information</info> >> </nested> >> </further> >> </some> >> </category> >> </categories> >> </category> >> </categories> >> </site> >> </sites> >> >> What I want would be: >> <sites> >> <site> >> <categories> >> <category name="root"> >> <categories> >> <category name="category_1"> >> <some> >> <further> >> <nested> >> <info info_id="1">Important Information</info> >> </nested> >> </further> >> </some> >> </category> >> </categories> >> </category> >> </categories> >> </site> >> </sites> >> >> I tried several approaches like: >> /site/sites//categories/category[@name = 'category_1'] >> or >> /site/sites//categories/category[@name != 'hidden'] >> or >> /site/sites//categories/category/some/further/nested/info[@info_id = >> '1'] >> >> But all I get is something like this: >> <category name="category_1"> >> <some> >> <further> >> <nested> >> <info info_id="1">Important Information</info> >> </nested> >> </further> >> </some> >> </category> >> >> What is missing to preserve the parent xml data? >> >> Any hint that will point me to the right direction would be very >> appreciated! >> >> Thank & Regards, >> >> Christian >> >> >> >> _______________________________________________ >> http://x-query.com/mailman/listinfo/talk >> http://x-query.com/mailman/listinfo/talk > > > -- > John Snelson, Oracle Corporation http://snelson.org.uk/john > Berkeley DB XML: http://oracle.com/database/berkeley-db/xml > XQilla: http://xqilla.sourceforge.net > _______________________________________________ > http://x-query.com/mailman/listinfo/talk > http://x-query.com/mailman/listinfo/talk
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