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Construct the absolute xpath (with node position)

Vallone, Philip Mr CTR USA AMC Philip.Vallone at us.army.mil
Tue Jun 17 12:56:29 PDT 2008

  Construct the absolute xpath (with node position)
Hi, is it possible to construct the absolute xpath (with node position)
from an xquery expression?

Take the following XML:


Take the following xquery:

for $path in //item/para
let $xpath := $path/string-join(ancestor-or-self::*/name(), '/')

Which returns:


Is it possible to construct an xquery expression to output the xpath
with node position:


Thanks for the help.



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