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How to run xquery dynamically on file listing from directory

Jonathan Robie jonathan.robie at redhat.com
Thu Apr 10 17:28:54 PDT 2008


  How to run xquery dynamically on file listing from
	directory
There is no such thing as XQuery 2.0, we're not that fast ;->

I honestly don't know what XML Spy uses as the XQuery processor. You'll 
have to look up the collection() function in the XML Spy documentation 
and see if they implement it and how. Or they may have some other way of 
implementing collections.

Jonathan

http://x-query.com/mailman/listinfo/talk wrote:
> I'm using XMLSpy to write and test my xquery and have specified:  xquery version "1.0";
> at the top of the query (although I think I can use 2.0 if necessary).  I'm running on Windows 5.1. 
>
> Selene
>
>  -------------- Original message ----------------------
> From: Jonathan Robie <http://x-query.com/mailman/listinfo/talk>
>   
>> What XQuery implementation are you using, in what environment?
>>
>> Jonathan
>>
>> http://x-query.com/mailman/listinfo/talk wrote:
>>     
>>> I'm a complete newbie at xquery and am trying to execute a query dynamically 
>>>       
>> on 
>>     
>>> all files in a given directory, rather than hardcoding a particular file into 
>>> the 'doc()' call.  I've tried using 'collection()' but am unclear as to how to 
>>> get it to work.
>>>
>>> I did see this thread on x-query.com:
>>>  Query Through Multiple Files
>>> but the closest anyone came to the answer I was hoping to find was to hardcode 
>>>       
>> a 
>>     
>>> *list* of files to traverse.
>>>
>>> Is there anyway to do something like:
>>>     for $x in collection("xmlfiles")
>>> where 'xmlfiles' is a subdirectory containing the actual xml files I want to 
>>> use?  I would need to know the exact syntax, as this is all new to me.
>>>
>>> Thanks!
>>>
>>> _______________________________________________
>>> http://x-query.com/mailman/listinfo/talk
>>> http://x-query.com/mailman/listinfo/talk
>>>   
>>>       
>
>   



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