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[XQuery Talk Mailing List Archive Home] [By Date] [By Thread] [By Subject] [By Author] [Recent Entries] [Reply To This Message] How to run xquery dynamically on file listing from directoryWei, Alice J. ajwei at indiana.eduThu Apr 10 16:50:54 PDT 2008
Hi,
Yes, you can do something like running several files at once using collection().
The caveat is that this means you are running all the files in that collection. To answer your question, you can do something like
let $x: = collection("xmlfiles")
return
<count>{count($x)}</count>
Hope this helps.
Alice
======================================================
Alice Wei
MIS 2008
School of Library and Information Science
Indiana University Bloomington
http://x-query.com/mailman/listinfo/talk
________________________________________
From: http://x-query.com/mailman/listinfo/talk [http://x-query.com/mailman/listinfo/talk]
Sent: Thursday, April 10, 2008 2:22 PM
To: http://x-query.com/mailman/listinfo/talk
Subject: How to run xquery dynamically on file listing from directory
I'm a complete newbie at xquery and am trying to execute a query dynamically on
all files in a given directory, rather than hardcoding a particular file into
the 'doc()' call. I've tried using 'collection()' but am unclear as to how to
get it to work.
I did see this thread on x-query.com:
Query Through Multiple Files
but the closest anyone came to the answer I was hoping to find was to hardcode a
*list* of files to traverse.
Is there anyway to do something like:
for $x in collection("xmlfiles")
where 'xmlfiles' is a subdirectory containing the actual xml files I want to
use? I would need to know the exact syntax, as this is all new to me.
Thanks!
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