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[XQuery Talk Mailing List Archive Home] [By Date] [By Thread] [By Subject] [By Author] [Recent Entries] [Reply To This Message] replacing a node in in-memory XMLRyan Grimm grimm at xqdev.comTue Nov 6 10:17:16 PST 2007
Hi Robert, I wrote a library to perform this task a while ago. You can find the library and some example calls at: http://xqzone.marklogic.com/svn/commons/trunk/memupdate/ I wrote it to be used with the MarkLogic Server so depending on what you're using you might need to make a few changes but they shouldn't be very major. --Ryan Robert Walpole wrote: > Hi, > > I am trying to figure out the best way to replace a node within an > in-memory XML fragment. > > For example, lets say I have the following fragment in memory… > > <communitygroup> > <group> > <name>Test</name> > <services> > <service value="true">2</service> > </services> > </group> > </communitygroup> > > …and want to replace the services node with the following… > > <services> > <service value="false">1</service> > <service value="true">2</service> > <service value="false">3</service> > </services> > > Is there a way of doing this in XQuery? > > Obviously I could use an XSL transformation, which would give me the > result I want, but maybe there is a more efficient way using XQuery? > > Thanks > Rob Walpole > Devon Portal Developer > Email http://x-query.com/mailman/listinfo/talk > Web _http://www.devonline.gov.uk_ > > > ------------------------------------------------------------------------ > > _______________________________________________ > http://x-query.com/mailman/listinfo/talk > http://x-query.com/mailman/listinfo/talk
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