replacing a node in in-memory XML

[Michael Kay]

In the absence of XQuery updates (still a draft W3C spec) it's quite a bit
harder to do this in XQuery than in XSLT: you basically have to organize the
recursive walk down the tree copying nodes as you go yourself "by hand". If
you are comfortable with XSLT then this is definitely a task where XSLT
currently wins. It will get a lot easier with XQuery updates.
 
Michael Kay
http://www.saxonica.com/

  _____  

From: http://x-query.com/mailman/listinfo/talk [mailto:http://x-query.com/mailman/listinfo/talk] On Behalf
Of Robert Walpole
Sent: 06 November 2007 15:05
To: http://x-query.com/mailman/listinfo/talk
Subject:  replacing a node in in-memory XML



Hi, 

I am trying to figure out the best way to replace a node within an in-memory
XML fragment. 

For example, lets say I have the following fragment in memory. 

<communitygroup> 
        <group> 
                <name>Test</name> 
                <services> 
                        <service value="true">2</service> 
                </services> 
        </group> 
</communitygroup> 

.and want to replace the services node with the following. 

<services> 
        <service value="false">1</service> 
        <service value="true">2</service> 
        <service value="false">3</service> 
</services> 

Is there a way of doing this in XQuery? 

Obviously I could use an XSL transformation, which would give me the result
I want, but maybe there is a more efficient way using XQuery?

Thanks 
Rob Walpole 
Devon Portal Developer 
Email http://x-query.com/mailman/listinfo/talk 
Web  <http://www.devonline.gov.uk> http://www.devonline.gov.uk 

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