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[XQuery Talk Mailing List Archive Home] [By Date] [By Thread] [By Subject] [By Author] [Recent Entries] [Reply To This Message] replacing a node in in-memory XMLRobert Walpole robert.walpole at devon.gov.ukTue Nov 6 15:05:26 PST 2007
Hi, I am trying to figure out the best way to replace a node within an in-memory XML fragment. For example, lets say I have the following fragment in memory... <communitygroup> <group> <name>Test</name> <services> <service value="true">2</service> </services> </group> </communitygroup> ...and want to replace the services node with the following... <services> <service value="false">1</service> <service value="true">2</service> <service value="false">3</service> </services> Is there a way of doing this in XQuery? Obviously I could use an XSL transformation, which would give me the result I want, but maybe there is a more efficient way using XQuery? Thanks Rob Walpole Devon Portal Developer Email http://x-query.com/mailman/listinfo/talk Web http://www.devonline.gov.uk -------------- next part -------------- An HTML attachment was scrubbed... URL: http://x-query.com/pipermail/talk/attachments/20071106/116e8d15/attachment.htm
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