|
[XQuery Talk Mailing List Archive Home] [By Date] [By Thread] [By Subject] [By Author] [Recent Entries] [Reply To This Message] calculated attribute/ namespace nameJohn Snelson john.snelson at oracle.comWed Aug 15 15:41:51 PDT 2007
Something like this will work: /ele/@*[node-name(.) = fn:QName($namespace, $attribute)] John Uwe Küssner wrote: > hello, > > a short question, i hope somebody can help. > > Let's say we have a XML documents like this: > > <ele xmlns:a="aa" xmlns:b="bb" name="foo" a:name="bar" > b:name="foobar" b:x="y" /> > > The namespace names and attributes are not known before runtime, during > runtime of a xquery script we have two variables of type string, for > example: > $namespace := "bb" > $attribute :="name" > > here is the question: how can we extract the value of the attribute > named $attribute with namespace name $namespace? > In the example the value of "b:name", i.e. "foobar". > > thank you very much > > _______________________________________________ > http://x-query.com/mailman/listinfo/talk > http://x-query.com/mailman/listinfo/talk
|
Purchase Stylus Studio Online Today!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|






