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[XQuery Talk Mailing List Archive Home] [By Date] [By Thread] [By Subject] [By Author] [Recent Entries] [Reply To This Message] problem with XupdateTitash Neogi titash_neogi at symantec.comTue Jan 10 01:48:39 PST 2006
Hello All, I am facing a small problem with Xupdate. I have a xml file <maps> <map> <prereq></prereq> <main></main> <result></result> </map> . . . </maps I am populating this xml file from a form using Xupdate. Below is the bit of code for this - _______________________________________ let $updt:= <xupdate:modifications version="1.0" xmlns:xupdate="http://www.xmldb.org/xupdate" > <xupdate:append select="doc('/db/content/map1.xml ')/maps"> <xupdate:element name="map"></xupdate:element> </xupdate:append> </xupdate:modifications> let $dummy:= xmldb:update($collection, $updt) (: creates a new /map node in the xml file :) (: update user inputs into /maps/map :) let $xupdate := <xupdate:modifications version="1.0" xmlns:xupdate="http://www.xmldb.org/xupdate" > <xupdate:append select="doc('/db/content/map1.xml')/maps/map"> <xupdate:element name="prereq">{$prereq}</xupdate:element> <xupdate:element name="main">{$main}</xupdate:element> <xupdate:element name="resultt">{$result}</xupdate:element> </xupdate:append> </xupdate:modifications> (: update the collection :) let $dummy2:= xmldb:update($collection, $xupdate) _______________________________________ This works fine but the only problem is that every time it goes and updates each map node with the content and also creates a new map node. So if I had <maps> <map> <prereq>test </prereq> <main>test2</main> <result>test3</result> </map> . . . </maps And I input a new node Prereq - tes5 Main - test6 Result - test7 The result is <maps> <map> <prereq>test </prereq> <main>test2</main> <result>test3</result> <prereq>test5 </prereq> <main>test6</main> <result>test7</result> </map> . <map> <prereq>test5 </prereq> <main>test6</main> <result>test7</result> </map> . . </maps Is there a way in which I can add a new node and not change/add to the existing nodes in the xml file? Thanks and Regards Titash
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