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[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Best way to create an XML document
On Sun, Apr 13, 2008 at 10:16 PM, Michael Kay <mike@s...> wrote:
>Or it might be simpler to put the serialized output
> through an XML parser if you need to check it.
I tried this approach with Xalan/Xerces, and following are my findings ...
public static void main(String[] args) {
try {
TransformerFactoryImpl tfi = new TransformerFactoryImpl();
TransformerHandler tHandler = tfi.newTransformerHandler();
tHandler.getTransformer().setOutputProperty(OutputKeys.INDENT, "yes");
String output = "output.xml";
tHandler.setResult(new StreamResult(new File(output)));
tHandler.startDocument();
tHandler.startElement("", "x", "x", null);
AttributesImpl attrs = new AttributesImpl();
attrs.addAttribute("", "attr1","attr1", "", "123");
attrs.addAttribute("", "attr2","attr2", "", "456");
tHandler.startElement("", "y", "y", attrs);
tHandler.startElement("", "z", "z", null);
tHandler.endElement("", "z", "z");
tHandler.endElement("", "y", "y");
tHandler.endElement("", "x", "x");
tHandler.endDocument();
if (isWellFormed(output)) {
Sstem.out.println("Generation of XML document is fine.");
/*
do something with the generated file
*/
}
else {
System.out.println("Generated XML document is not well-formed.");
}
}
catch(Exception ex) {
ex.printStackTrace();
}
}
private static boolean isWellFormed(String output) {
try {
XMLReaderAdapter xra = new XMLReaderAdapter();
InputSource is = new InputSource(new FileInputStream(output));
xra.parse(is);
return true;
}
catch(Exception ex) {
return false;
}
}
This code post processes the serialized XML output (i.e., check for
well-formedness).
I think this makes me happy :)
--
Regards,
Mukul Gandhi
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