[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: How to get XPath in a XSLT shylesheet
Long JingJun wrote: > Hi all, > > My original target is to get the XPath to identify the location of an element in the XML output (as location attribute for an example). So that I can find the original place in the source file when I go through the generated XML output. What I mean full XPath is like this: /document/chapter[2]/section[3]/subject[1]/para[2] > Heres the code we use in Schematron (I think from David Carlisle originally?) <xsl:template match="*|@*" mode="get-full-path"> <xsl:apply-templates select="parent::*" mode="get-full-path"/> <xsl:text>/</xsl:text> <xsl:if test="count(. | ../@*) = count(../@*)">@</xsl:if> <xsl:value-of select="name()"/> <xsl:text>[</xsl:text> <xsl:value-of select="1+count(preceding-sibling::*[name()=name(current())])"/> <xsl:text>]</xsl:text> </xsl:template> (XSLT question are better dealt with on the mulberry XSLT list.) Cheers Rick Jelliffe
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