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xsl file problem

• To: xml-dev@l...
• Subject: xsl file problem
• From: "nick tsirakis" <tsirman@h...>
• Date: Thu, 29 Apr 2004 12:41:28 +0000
• Bcc:

well i have a problem with something,
i have an xml file and i have created an xsl file to parse my data for my 
php page.
the xsl code is here:
--------------------------
<?xml version="1.0"?>
<xsl:stylesheet
	xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
	version="1.0">
<xsl:template match="code">
</xsl:template>


<xsl:template match="categorylist">
<table width="365" border="0">
    <xsl:apply-templates select="category"/>
</table>
</xsl:template>

<xsl:template match="category" />
<xsl:template match="category" mode="next" />

<xsl:template match="category[position() mod 2 = 1]">
    <tr>
	<xsl:call-template name="nodename" />
    </tr>
</xsl:template>

<xsl:template match="category[position() mod 2 != 1]" mode="next">
    <xsl:call-template name="nodename" />

</xsl:template>

<xsl:template name="nodename">
    <td width="50%">
        <font face = "Verdana" size = "1" color = "#000066">
	<a HREF="index.php?nodeid={nodeid}&amp;nodename={nodename}">
	<xsl:value-of select="nodename" /></a></font>
	<font face = "Verdana" size = "1" color = "#666666"> (<xsl:value-of 
select="sitecount" />)</font>
    </td>
    <xsl:apply-templates select="following-sibling::*[1]" mode="next" />

</xsl:template>

</xsl:stylesheet>
-------------------------
i want in this code to have a sorting of "nodename" but i tried to put the

<xsl:sort select="nodename"/>

inside this code nut it does not work......

thanks for any help

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