[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] DTD replacement
Hello, I have a question: how to replace DTD in some XML document in the most robust way? Suppose that I have some xml: <?xml version='1.0'?> <!DOCTYPE page SYSTEM "some.dtd"> <page> ... </page> That xml file comes from some user who uploads it via web interface and the user could upload bad xml containing reference to his own DTD or even internal dtd. The question is how to replace DTD in uploaded file in order to validate against my own DTD? Can I achieve it using standard SAX parser? -- Best regards, Pavel mailto:pavel@a...
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|