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Re: converting XML Schema to DTD

• To: "Banerjee, Saurabh" <sabanerjee@a...>
• Subject: Re: converting XML Schema to DTD
• From: John Cowan <jcowan@r...>
• Date: Mon, 28 Jan 2002 16:41:41 -0500
• Cc: "'xml-dev@l...'" <xml-dev@l...>
• References: <93CB722CF8BBD411AE140008C791E71603E3CAEB@p...>
• User-agent: Mozilla/5.0 (X11; U; Linux i686; en-US; rv:0.9.6) Gecko/20011120

Banerjee, Saurabh wrote:

> Thanks John! Actually the question was what is the equivalent of the
> following schema definition in DTD terms?


Ah.  DTDs have no equivalent of xs:all at all.   You either have
to tighten up the content model and require ordering, or loosen
it and allow multiple fnames and lnames.

My advice, if this is a real problem and not a mere test, would
be to go with commonName, sortName anyhow, because you cannot
be guaranteed to have just two parts to a name, nor which part is
appropriate to sort on:

<personnel>
    <commonName>George W. Bush</commonName>
    <sortName>Bush, George W.</sortName>
</personnel>

vs.

<personnel>
    <commonName>Davíð Oddsson</commonName>
    <sortName>Davíð Oddsson</sortName>
</personnel>


-- 
John Cowan <jcowan@r...>     http://www.reutershealth.com
I amar prestar aen, han mathon ne nen,    http://www.ccil.org/~cowan
han mathon ne chae, a han noston ne 'wilith.  --Galadriel, _LOTR:FOTR_

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  • RE: converting XML Schema to DTD
    • From: "Banerjee, Saurabh" <sabanerjee@a...>

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