[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: XPath: position of the parent ?
Hi Gerd, > How do I express in XPath the position of the parent of a node ? I > guess it must be something like '../position()', but this don't > work. The terminology that's used in XPath can be a little confusing here. In XPath, the only node that has a position is the context node - the node you're currently looking at - within the context node list - the list of nodes that you've selected. If you think about it like that, then the position of a node's parent is always 1, because when you select the parent of a node you only select one node. But I think you're probably after the position of a node's parent node *in the list of its siblings*. You can get this by counting how many preceding siblings the parent node has, and adding 1: count(../preceding-sibling::node()) + 1 (You may want to narrow down the types of preceding siblings that you count, to prevent yourself from counting whitespace.) Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|