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[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Tree view from IE5
Hi Jens,
is this what you want?
You can get it by intercepting the stream that your server sends to your
client. This is IE5 beta 2's script and style sheet. I havn't looked at the
IE5 release yet, but I suspect that MS have somehow made it more difficult
to intercept the stream.
the document I sent was <xdoc>some simple text</xdoc>, and this is how it
comes wrapped!
Frank
<HTML><HEAD>
<STYLE>
BODY{font:10pt Verdana}
.c{cursor:hand}
.b{color:red;font-family:FixedSys}
.e{margin-left:1em;text-indent:-1em;margin-bottom:3px}
.k{margin-left:1em;text-indent:-1em;margin-bottom:3px}
.t{color:#444444}
.a{color:#444444}
.tx{font-weight:bold}
.db{text-indent:0px;margin-left:2em;margin-top:0px;margin-bottom:0px;font:9p
t Courier;color:#0044BB}
.di{font:9pt Courier;color:#0044BB}
.d{color:#0044BB}
.pi{color:#0044BB}
.cb{text-indent:0px;margin-left:2em;margin-top:0px;margin-bottom:0px;font:9p
t Courier;color:#0044BB}
.ci{font:9pt Courier;color:#0044BB}
PRE{margin:0px;display:inline}
</STYLE>
<SCRIPT>
<!--
function initState()
{
var pres=document.all.tags("PRE");
for (var i=0;i<pres.length;i++)
{
var cparent=pres(i).parentElement;
if (cparent.className=="ci")
{
if (cparent.children(0).innerText.indexOf("\n")>0)
{
cparent.className="cb";
cparent.style.display="block";
cparent.parentElement.children(0).className="c";
cparent.parentElement.children(0).children(0).innerText="-";
}
}
if (cparent.className=="di")
{
if (cparent.children(0).innerText.indexOf("\n")>0)
{
cparent.className="db";
cparent.style.display="block";
cparent.parentElement.children(0).className="c";
cparent.parentElement.children(0).children(0).innerText="-";
}
}
}
}
function changeState(e)
{
mark=e.children(0).children(0);
if (mark.innerText=="+")
{
for (var i=1;i<e.children.length;i++)
e.children(i).style.display="block";
mark.innerText="-";
}
else if (mark.innerText=="-")
{
for (var i=1;i<e.children.length;i++)
e.children(i).style.display="none";
mark.innerText="+";
}
}
function changeChunkState(e)
{
mark=e.children(0).children(0);
contents=e.children(1);
if (mark.innerText=="+")
{
if (contents.className=="db"||contents.className=="cb")
contents.style.display="block";
else
contents.style.display="inline";
mark.innerText="-";
}
else if (mark.innerText=="-")
{
contents.style.display="none";
mark.innerText="+";
}
}
function document_click()
{
e=window.event.srcElement;
if (e.className!="c")
{e=e.parentElement;if (e.className!="c")
{
return;
}
}
e=e.parentElement;
if (e.className=="e") changeState(e);
if (e.className=="k") changeChunkState(e);
}
document.onclick=document_click;
--></SCRIPT>
<SCRIPT FOR="window" EVENT="onload">initState();</SCRIPT>
</HEAD>
<BODY class="st"><DIV class="e">
<DIV STYLE="margin-left:1em;text-indent:-2em">
<SPAN class="b"> </SPAN>
<SPAN class="t"><xdoc</SPAN><SPAN class="t">></SPAN><SPAN
class="tx">some simple text</SPAN><SPAN class="t"></xdoc></SPAN>
</DIV></DIV>
</BODY>
</HTML>
----- Original Message -----
From: Lippmann, Jens <LippmannJ@M...>
To: <xml-dev@i...>
Sent: Monday, March 22, 1999 9:01 AM
Subject: Tree view from IE5
>Is there a way to "borrow" the stylesheet that creates the XML tree in IE5
>for XML files without an attached stylesheet, or is the tree hardcoded into
>the msxml.dll?
>
>Jens
>
>
>
>xml-dev: A list for W3C XML Developers. To post, mailto:xml-dev@i...
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>
>
xml-dev: A list for W3C XML Developers. To post, mailto:xml-dev@i...
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