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hardik mehtaSubject: looping to generate 2 columnar table !
Author: hardik mehta
Date: 23 Nov 2005 07:51 AM
Hi all,
First greetings to all. I am a new member of this forum and also relatively new to XSLT.

I am trying to generate an xsl:fo file using xml document and xslt.
now, I requre 2 columnar table looping through node in xml.
To be precise it looks like following..
xml file:
<some-node>
<node-of-interest>
<sub-node1> val1 </sub-node1>
</node-of-interest>
<node-of-interest>
<sub-node1> val2 </sub-node1>
</node-of-interest>
<node-of-interest>
<sub-node1> val3 </sub-node1>
</node-of-interest> ........
</some-nodes>

output required:
|-------|----------|
|_col1_|__col2_|
|val1 | val2 |
_____________
|val3 | val4 |

|valN | |
_______ ____|

and i wanted to select row according to the fn:position() is even or the final node ....
xsl logic (not written in std syntax to save time and space )
<table>
<xsl:for-each select="some-nodes/node-of-interest" >
<if test="position() odd">
<row>
</if>
<cell>
<xsl:value-of select="sub-node1" />
</cel>
<cell>
<xsl:value-of select="sub-node1" />
</cel>

<if test="position() even or last()">
</row>
</if>
</xsl:for-each>
</table>

this implementation fails because of incomplte <row> element !!!

is there any other way to loop through ... may be with the step of 2 nodes ??


....................... any help ???

thanks,
Hardik
Postnext
(Deleted User) Subject: looping to generate 2 columnar table !
Author: (Deleted User)
Date: 23 Nov 2005 08:30 AM
Hardik,
I would try something like this:
<xsl:for-each>
<xsl:if (odd)>
<row>
- generate cell for position()
- generate cell for position()+1 if it exists
</row>
</xsl:if>

Good luck,
- clyde
Postnext
hardik mehtaSubject: looping to generate 2 columnar table !
Author: hardik mehta
Date: 23 Nov 2005 08:45 AM
Hi,

thanks,

but how to select the next item inside for-each with position ?

acutally I am not selecting all the nodes I have also applied condition

like..

<xsl:for-each select="node-of-interest[suvalue = test]">
.....


Hardik
Postnext
(Deleted User) Subject: looping to generate 2 columnar table !
Author: (Deleted User)
Date: 23 Nov 2005 09:09 AM
Hardik,

First, I think FO has facilities for automatically generating 2 column output. I suggest you investigate that.

But, in your example, you can do something like this:
<xsl:variable name="nodes" select="node-of-interest[suvalue = test]"/>
<xsl:for-each select="$nodes">
<xsl:if odd>
<row>
- generate cell for position()
- generate cell for position()+1 if it exists
</row>
</xsl:if>
</xsl:for-each>

- clyde
Postnext
hardik mehtaSubject: looping to generate 2 columnar table !
Author: hardik mehta
Date: 23 Nov 2005 09:37 AM
Hi,

thanks ..

it seems to be working..

but the only problem left is when I try to access the second cell inside for-each loop and it is in both the cases with variable $nodes and without it


self::node()[position="nextIndex"] it gives me blank values

Postnext
(Deleted User) Subject: looping to generate 2 columnar table !
Author: (Deleted User)
Date: 23 Nov 2005 10:35 AM
Hardik, we are almost there...

<xsl:variable name="nodes" select="/root/data[substring(.,1,1)='a']"/>
<xsl:for-each select="$nodes">
<xsl:if test="(position() mod 2)=1">
<xsl:variable name="nextIndex" select="position()+1"/>
<row>
- generate cell for select="."
- generate cell for select="$nodes[$nextIndex]"
</row>
</xsl:if>
</xsl:for-each>

- clyde
Posttop
hardik mehtaSubject: looping to generate 2 columnar table !
Author: hardik mehta
Date: 24 Nov 2005 03:25 AM
Hi clyde,

thank u verymuch for ur help !

everything is working now...


Hardik
   
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