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Topic  
Postnext
JJJ JJJSubject: apply templates in order
Author: JJJ JJJ
Date: 25 Oct 2005 09:44 AM
I want to rearrange the order of my XML file via XSLT.
At the moment I am doing this by writing out 10 different <xsl:apply-template select=""> statements.
This seems to take twice as long as just using the <xsl:apply-templates/> element.
Is there a quicker way to rearrange the order that nodes appear or is this the only way?
Thanks.
Postnext
(Deleted User) Subject: apply templates in order
Author: (Deleted User)
Date: 25 Oct 2005 10:04 AM
You can publish your input XML file and current XSLT here. Using this data we will try to simplify your XSLT.
Postnext
JJJ JJJSubject: apply templates in order
Author: JJJ JJJ
Date: 25 Oct 2005 11:45 AM
Originally Posted: 25 Oct 2005 11:36 AM
Here is a sample of the XSLT & XML. I also had a question on the repetetive nature of the select element. For example in the candidate template, I continually use <xsl:value-of select="accname"/>. I did this because I do not want every element from the XML to be transformed (some have been deliberately left out) but there may be a quicker way of doing this?


UnknownStylesheet_Version_3.0.xsl
XSLT

Unknowntest(10).xml
Input XML
Posttop
(Deleted User) Subject: apply templates in order
Author: (Deleted User)
Date: 25 Oct 2005 02:19 PM
You can use <xsl:copy-of> everywhere you are just copying subtree,
for example this:

<xsl:template match="perminvitem">
<perminvitem>
<charge>
<xsl:value-of select="charge"/>
</charge>
<description>
<xsl:value-of select="description"/>
</description>
<empid>
<xsl:value-of select="empid"/>
</empid>
<percentcharge>
<xsl:value-of select="percentcharge"/>
</percentcharge>
<perminv>
<xsl:value-of select="perminv"/>
</perminv>
<perminvoiceitems>
<xsl:value-of select="perminvoiceitems"/>
</perminvoiceitems>
<salary>
<xsl:value-of select="salary"/>
</salary>
<startdate>
<xsl:value-of select="startdate"/>
</startdate>
</perminvitem>
</xsl:template>

can probably be changed into this:

<xsl:template match="perminvitem">
<xsl:copy-of select="."/>
</xsl:template>

as long as source and target sub-trees are exactly the same.
   
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