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suresh chintaSubject: Escape a character in the string
Author: suresh chinta
Date: 20 Jan 2009 12:13 AM
Hello all:

I am trying to replace a character (underscore) '_' with space ' '
in the following manner :

<xsl:variable name="string"><xsl:value-of select="value/item[@name='FieldName']"/></xsl:variable>

<xsl:if test="contains($string, '_')">
<xsl:value-of select="substring-before($string, '_')" />
<xsl:text>&#xa0;</xsl:text>
<xsl:value-of select="substring-after($string, '_')" />
</xsl:if>

If the value is 'First_Name' it is printed as 'First Name'. The problem is, if the value is only 'Account' then blank string is displayed.
How can this problem be fixed?
Thanks

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Tony LavinioSubject: Escape a character in the string
Author: Tony Lavinio
Date: 20 Jan 2009 10:58 AM
First, instead of this:

<xsl:variable name="string"><xsl:value-of select="value/item[@name='FieldName']"/></xsl:variable>

get into the habit of writing this, which doesn't require creating
a small tree, but instead just assigns the atomic value to the variable:

<xsl:variable name="string" select="value/item[@name='FieldName']"/>

Next, you never told the code what to do if $string does not contain
an underscore. Try this:

<xsl:choose>
<xsl:when test="contains($string, '_')">
<xsl:value-of select="concat(substring-before($string, '_'), '&#xa0;', substring-after($string, '_'))"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"/>
</xsl:otherwise>
<xsl:choose>

In the future, general XSLT questions are best handled on the
general-purpose XSL-LIST run by Mulberry Technologies

Posttop
suresh chintaSubject: Escape a character in the string
Author: suresh chinta
Date: 20 Jan 2009 11:03 AM
Thank you. Will make a note of it to post the question at a proper place.

 
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