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Matt Adams

Subject: Searching simplest XPATH matching node outputter
Author: Matt Adams
Date: 18 Sep 2004 03:10 PM

I am searching for a xslt stylesheet which simply outputs (at the console
or into a file) all matching nodes (including their individual attributes)
for a given XPath expression and a given (valid) xml document.

How does such a XSLT stylesheet look like?

Matt

Minollo I.

Subject: Searching simplest XPATH matching node outputter
Author: Minollo I.
Date: 18 Sep 2004 03:32 PM

Something like this?
(it assumes you are running it against books.xml, which is part of the example documents bundled with Stylus Studio)

<?xml version='1.0' encoding='utf-8'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="/">
<result-set>
<xsl:apply-templates select="//book[@bookid>4]"/>
</result-set>
</xsl:template>

<xsl:template match="*">
<xsl:copy-of select="."/>
</xsl:template>

</xsl:stylesheet>

Instead of the hardcoded XPath expression you could use a global parameter that you can set from a command line; and you can of course customize the way the node is rendered in <xsl:template match="*"> (maybe including only the name and the attributes, but not the children element...).

Hope this helps,
Minollo

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